Question

THE PERIMETER OF AN EQUILATERAL TRIANGLE IS 12CM

A= WHAT IS THE LENGTH OF EACH SIDE OF THE TRIANGLE

B= WHAT IS THE SIZE OF EACH ANGLE OF THE TRIANGLE

Answer 1

A) $P=3a\to a=\frac{P}{3}=\frac{12}{3}=4 cm.$

B) $\alpha=\frac{180^0}{3}=60^0.$