Question

4. A classroom is 38 feet long, 24 feet wide and 10 feet high. Determine the volume and surface area.

Answer 1

The shape of the classroom is a parallelogram.

1) The formula of a volume of a parallelogram is:

$$V = l * w * h$$

where

- l is for length,

- w is for width

- h is for high.

We have $l = 38$ feet, $w = 24$ feet and $h = 10$ feet.

So, $V = 38 * 24 * 10 = 9120$ (feet^3)

2) The surface area of a parallelogram is the sum of all side's areas, which are rectangles.

There are 6 sides. The formula for each side's area is:

$S = a * b$, where $a$ is length of a rectangle, $b$ - width.

So, the surface area is $S = 2*S_1 + 2*S_2 + 2*S_3 = 2*l*w + 2*l*h + 2*w*h = 1824 + 760 + 480 = 3064$ (feet^2).

Answer: the volume of the class is 9120 cubic feet and the surface area is 3064 square feet.