Answer to Question #230110 in Geometry for Mack

Question

You have a box that measures 2 meters x 2 meters x 6 meters. What is the longest piece of rebar (inside diagonal) that could fit in this box? What assumption is necessary for this calculation?

Answer 1

length (l)=2 meters

breadth(b)=2 meters

height(h)=6 meters

the longest piece of rebar(x)

$x=\sqrt{l^2+b^2+h^2}\\x=\sqrt{^2+2^2+6^2}\\x=\sqrt{4+4+36}\\x=\sqrt{44}\\x=2\sqrt{11}$

so the longest piece of rebar =$2\sqrt{11}$ meters

for this calculation l, b ,h and x assumption are necessary.