Question #22975

Perimeter, Circumference, and Area

A garden is in the shape of an isosceles trapezoid with legs of 15 ft and bases of 10 ft and 28 ft. How many ft of fencing will be needed to enclose the garden? If all the area can be utilized, how many square feet of garden will be available for planting?

Expert's answer

28=10+2128 = 10 + 2*1l=(2810)/2=9l = (28 - 10)/2 = 9


By the Pythagorean theorem:


h=152922=12h = \sqrt{ \frac{15^2 - 9^2}{2} } = 12P=215+10+28=68P = 2*15 + 10 + 28 = 68


P - perimeter


S=28+10212=228S = \frac{28 + 10}{2*12} = 228


S - area

Answer: 68 ft of fencing will be needed to enclose the garden, 228 square feet of garden will be available for planting.

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