Answer to Question #228675 in Geometry for irvon tyuiol

Question

Given a triangle with sides 7m, 8m and 3m. What is 50% the area of this triangle?

Answer 1

Using Heron's formula ;

Area(Triangle) =$\sqrt {s(s-a) (s-b) (s-c)}$

Where $s=\frac{(7+8+3) }{2} =9$

Area Triangle =$\sqrt {9(9-7) (9-8) (9-3)}$

Area Triangle =$\sqrt {108}=10.39m^2$

50%Area Triangle =$0.5×10. 39m^2$ $=5.196cm2$