Find an equation of the circle whose diameter has endpoints (-4,6) and (6,-4)
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Expert's answer
2013-01-08T11:45:03-0500
equation of the circle: (x-x0)^2+(y-yo)^2=r^2 where x0, y0 - center, r- radius r=d/2 d^2=(-4-6)^2+(6+4)^2=200 r^2=d^2/4=50 x0=(-4+6)/2=1 y0=(6-4)/2=1 Answer: (x-1)^2+(y-1)^2=50
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