Question

For circle H, JN = 3, NK = x, LN = 2, and NM = 6. Solve for x.

Answer 1

As per the given question,

NJ = 3,

NK = x,

LN = 2,

And

NM = 6.

when two chords intersects each other, then the product of their segments is equal.

JN x NK = LN x NM

Now, substituting the values,

$\Rightarrow 3\times x=2\times 6$

$\Rightarrow x = \frac{12}{3} = 4$

$\Rightarrow x = 4$