Question #21358

Please solve this que with detailed explanation. You can see the pdf for figure.

https://www.dropbox.com/s/4kskjn5gyrv70dh/1.pdf

Expert's answer

Question 21358

Please find the angles which are not given. Please see the pdf and find the angle "e".

Solution.

Since SACESA||CE and SESE intersects them, then S=E=44\angle S = \angle E = 44{}^{\circ}.

The sides SHSH and AHAH of the triangle SHA\triangle SHA are equal to a radius of a circle. Thus, SH=AHSH = AH. It follows that S=A=44\angle S = \angle A = 44{}^{\circ} and H=180244=92\angle H = 180{}^{\circ} - 2 \cdot 44{}^{\circ} = 92{}^{\circ}.

So e=18092=88\angle e = 180{}^{\circ} - 92{}^{\circ} = 88{}^{\circ}.

Since SACESA||CE and CACA intersects them, we have A=C=44\angle A = \angle C = 44{}^{\circ}.

Answer. e=88\angle e = 88{}^{\circ}

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