Answer to Question #210753 in Geometry for Russel

Question

What is the weight of a steel plate 15 ft. long, 4 ft. wide, and 5/8 inch thick, if the steel weights 475 lb./ft.^3?

Answer 1

the formula of to find weight is $m = \rho V = \rho abc$

$a = 15ft$, $b = 4ft$, 1 inch is equal to  $\frac{1}{12} ft:$ $c = \frac{1}{12}*\frac{5}{8}=\frac{5}{96}ft$

$\rho = 475 \frac{lb}{ft^3}$

$m = 15ft*4ft*\frac{5}{96}ft*475\frac{lb}{ft^3}=1,484.375lb$