Traffic going has a high of 18" and a diameter 7" to the nearest 10th find the amount of space the cone occupies
V=13Sh=13πr2h=13π3.52∗18=230.907056V=\frac1 3Sh=\frac1 3\pi r^2h=\frac1 3 \pi3.5^2*18=230.907056V=31Sh=31πr2h=31π3.52∗18=230.907056
Answer: 230.907056
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