If the sides of the parallelogram and an included angle are 6, 10 and 100 degrees respectively, find the length of the larger diagonal.
let a=6, b=10, diagonal =d
d2=a2+b2−2abcos100o=62+102−2×6×10cos100od^2=a^2+b^2-2abcos100^o=6^2+10^2-2\times6\times 10 cos100^od2=a2+b2−2abcos100o=62+102−2×6×10cos100o
d2=36+100+20.76=156.76d^2=36+100+20.76=156.76d2=36+100+20.76=156.76
d=156.76=12.52d=\sqrt{156.76}=12.52d=156.76=12.52
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