in a triangle with the side lengths 5, 7, 9 length units, the largest angle x is
A) x>90
B) x=90
C) x<90
We have given the sides of triangle "5,7,9."
Largest angle would be on the opposite of largest side,
We know,
"cosA = \\dfrac{b^2+c^2-a^2}{2bc}"
"cosA = \\dfrac{5^2+7^2-9^2}{2 \\times 5 \\times 7}"
"cosA = -\\dfrac{21}{70}"
"A = 107.45^{\\circ}"
Hence the angle will be greater than "90^{\\circ}"
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