Question
1) TL is parallel to CB. So, if CL intersects TL and CB, then the angle TLC equal to angle LCB. We have:
∠TLC=∠LCB.
2) AT is parallel to LC. So, if TL intersects AT and LC, then the angle ATL is equal to the angle TLC. We have:
∠ATL=∠TLC.
3) We have:
{∠TLC=∠LCB∠ATL=∠TLC⇒∠ATL=∠LCB. Proved.
Answer: Proved.