Question #186239
The perpendicular distance d from the point (2,3) to the line 3x+4y+2=0 is
Expert's answer
d= (Am+Bn+C)/(A2 +B2)1/2
d=(3x2+4x3+2)/(32+42)1/2
d=20/5
d= 4 units
Learn more about our help with Assignments: Geometry
The perpendicular distance d from the point (2,3) to the line 3x+4y+2=0 is
d= (Am+Bn+C)/(A2 +B2)1/2
d=(3x2+4x3+2)/(32+42)1/2
d=20/5
d= 4 units
