Find the volume and the lateral area of a frustum of a right circular cone whose radii are 4 cm and 8 cm, and the slant height is 6 cm.
R1=4 cm, R2=8 cm, l=6 cm
Formula lateral area S=1/3"\\pi"(R1+R2)l consequently S=1/3"\\pi"(4+8)6=24"\\pi"=75.36
Formula volume V=1/3"\\pi" H (R12+R1R2+R22) for H2=l2-(R2-R1)2 consequently H="\\sqrt{36-16}" =2"\\sqrt{5}" and
V=1/3"\\pi" 2"\\sqrt{5}" (16+32+64)=224"\\pi""\\sqrt{5}" /3=524.25
Answer: S=24"\\pi"=75.36 cm2 and V=224"\\pi""\\sqrt{5}" /3=524.25 cm3
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