Answer to Question #160933 in Geometry for [e-mail]

Question

to devide a line segment BC internally in a ratio 3:5 we draw a ray BX such that CBX is an acute angle​

Answer 1

$$3+5=8 (points)$$

To divide a line segment BC in the ratio 3:5

Step1 : Draw a line segment BC of some length

Step 2 : Draw a line segment BX such that ∠CBX is an acute angle

Step 3: Take 8 point on BX of Equal length one by one ( consecutively)

Step 4 : Join 8th Point with C as a straight line

Step 5 : Draw a line parallel to line drawn in step 4 such that it passes through 3rd point of step 3 and intersect BC at M