Question #158467

In a quadrilateral OABC, D is the midpoint of BC and E is the point on AD such that AE : ED = 2 : 1. Given that OA = A, OB = B, and OC = c express OD and OE in terms of a,b and c.


Expert's answer

The question does not contain complete information that is needed to resolve it. Depending on angles BOC\angle BOC and AOB\angle AOB , the answer may be different. If we change these angles and and all conditions are done, OD and OE change. It is shown on the picture


Solution:

Introduce vectors: OA=a\overrightarrow{OA}=\overrightarrow{a} , OB=b\overrightarrow{OB}=\overrightarrow{b} , OC=c\overrightarrow{OC}=\overrightarrow{c} .

Then OD=b+c2\overrightarrow{OD}=\frac{\overrightarrow{b}+\overrightarrow{c}}{2} (used BD = DC).

DA=aOD=ab+c2=2a(b+c)2\overrightarrow{DA}=\overrightarrow{a}-\overrightarrow{OD}=\overrightarrow{a}-\frac{\overrightarrow{b}+\overrightarrow{c}}{2}=\frac{2\overrightarrow{a}-(\overrightarrow{b}+\overrightarrow{c})}{2} .

AD and AM are medians. E is the point of the intersection of AD and AM. In this point each median divides as 2:1 (AE:AD = 2:1). That's why

DE=13DA=2a(b+c)6\overrightarrow{DE}=\frac13\overrightarrow{DA}=\frac{2\overrightarrow{a}-(\overrightarrow{b}+\overrightarrow{c})}{6}

OE=OD+DE=b+c22a(b+c)2=a+b+c3\overrightarrow{OE}=\overrightarrow{OD}+\overrightarrow{DE} =\frac{\overrightarrow{b}+\overrightarrow{c}}{2}-\frac{2\overrightarrow{a}-(\overrightarrow{b}+\overrightarrow{c})}{2}=\frac{\overrightarrow{a}+\overrightarrow{b}+\overrightarrow{c}}{3}

OD=OD=b+c2=12(b+c)2=12b2+c2+2bccosBOCOD=|\overrightarrow{OD}|=|\frac{\overrightarrow{b}+\overrightarrow{c}}{2}|=\frac12\sqrt{(\overrightarrow{b}+\overrightarrow{c})^2}=\frac12\sqrt{b^2+c^2+2bc\cos{\angle{BOC}}}

OE=OE=a+b+c3=13(a+b+c)2=OE=|\overrightarrow{OE}|=|\frac{\overrightarrow{a}+\overrightarrow{b}+\overrightarrow{c}}{3}|=\frac13\sqrt{(\overrightarrow{a}+\overrightarrow{b}+\overrightarrow{c})^2}=

=13a2+b2+c2+2(abcosAOB+bccosBOC+accosAOC)=\frac13\sqrt{a^2+b^2+c^2+2(ab\cos{\angle{AOB}}+bc\cos{\angle{BOC}}+ac\cos{\angle{AOC}})}

An answer depends on angles BOC\angle BOC , AOB\angle AOB and AOC=BOC+AOB\angle AOC = \angle BOC+ \angle AOB.

We are free to change them without breaking any condition (as shown on the picture). So these angles cannot be expressed in terms of a, b and c.


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