ABC is a triangle and P, Q are the midpoints of AB, AC respectively. If AB = 2x
and AC = 2y, express the vectors (i) BC, (ii) PQ, (iii) PC, (iv) BQ in terms of x
and y. What can you deduce about the directed line-segments BC and PQ?
(Everything below is vectors)
So, as 2x + BC = 2y, we get BC = 2y - 2x
As x + PQ = y, we get PQ = y - x
As x + PC = 2y, we get PC = 2y - x
As 2x + BQ = y, we get BQ = y - 2x
Something we can deduce about the directed line-segments BC and PQ is that
BC = 2PQ, so they are parallel.
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