Question

The area

of an equilateral triangle is 9 √3

square feet. Find a side of the triangle.

Answer 1

Let $a=$ the side of the equilateral triangle. Then

$$A=\dfrac{a^2\sqrt{3}}{4}$$

Given $Area=9\sqrt{3}\ ft^2.$

$$\dfrac{a^2\sqrt{3}}{4}=9\sqrt{3}, a>0$$

$$a^2=36$$

$$a=6$$

The side of the given equilateral triangle is 6 foot.