Question

The area of a triangle is 18 square meters, and the base of the triangle is 9 meters.

Find the altitude of the triangle.

Answer 1

$$Area=\dfrac{1}{2}\times base \times altitude$$

$$altitude=\dfrac{2\times Area}{base}$$

$$altitude=\dfrac{2\times 18m^2}{9m}=4m$$

The altitude of the triangle is 4 meters.