Question

m<rxq =(x+15)° m<rxs=(5x-7)° m<qxs =(3x+5)° find the x value and m<rxs

Answer 1

Solution:

$m<RXQ+m<QXS=m<RXS$

$x+15+3x+5=5x-7$

$4x+20=5x-7$

$4x-5x=-20-7$

$-1x=-27$

$x=27$

$m<RXS=5x-7=5*27-7=128\degree$

Answer:

$x=27$ , $m<RXS=128\degree$