A. Cylinder
B. Volume of a cylinder ="\\pi r^2h\\\\"
"=\\frac{22}{7}\\times 3^2 \\times 10\\\\\n=282.8571419m^3\\\\\n\\approx 282.857m^3"
C. The cover area of the field dug out is "\\pi r^2". Since the cover is circular.
"=\\frac{22}{7} \\times 3^2\\\\\n=28.2857m^2\\\\\n\\approx 28.29m^2"
D. Total inner surface area "=2\\pi r(r+h)\\\\\n=2.\\frac{22}{7}.3(3+10)\\\\\n=245.14286m^2\\\\\n\\approx 245.14m^2"
E. "1m^3=Rs50\\\\\n282.857m^3=282.857\\times Rs50\\\\\n=Rs14142. 85"
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