Consider a regular square pyramid
Let "a=" the base edge, "h=" the altitude, and "l=" the lateral edge.
The volume "V" of the of a regular square prism is
Then
"a=\\sqrt{\\dfrac{V}{h}}"From the right triangle
"a=\\sqrt{\\dfrac{1200}{20(\\dfrac{\\sqrt{3}}{2})}}=2\\sqrt{10\\sqrt{3}}(cm)"
"a=2\\sqrt{10\\sqrt{3}}\\ cm"
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