Area of right circular cylinder is "A= 2\\pi r h" and volume is "V= \\pi r^2 h" . Thus we have
"2\\pi rh= 90 \\\\\nrh =\\cfrac{45}{\\pi}......Eq[1]\\\\ \nr^2 h=\\cfrac{225}{\\pi}.......Eq[2]"Now dividing Eq[2] by Eq[1]...
"r=\\cfrac{225}{45}\\\\\nr= 5cm.....Ans"radius of right circular cylinder is 5 cm.
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