Altitude, h = 12m
Volume, V = 196m³
V = a²*(h/3)
Where a = base edge
a² = V/(h/3)
a² = 3V/h
a² = (3*196)/12
a² = 49
a = 7m
The altitude divides the base edge into 2, forming a right angle triangle.
Therefore a' = 3.5m
Taking one of the triangles:
l² = (a')² + h²
where l = slant height
l² = (3.5)² + 12²
l² = 156.25
l = 12.5m
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