Question #148756

__24. A prismatoid has an upper base of 90%, a lower base of 2100%, an altitude of 100 cm, and a midsection of 120? What is its volume?


a) 7000 cm3

b) 11 500 cm3

c) 13 000 cm3

d) 17 500 cm3


25. Find the midsection of a frustum of a square pyramid if its lower base is 20 cm on a side, its upper base is 12 cm on a side, and the altitude of the frustum is 14 cm.


a)144 cm2

b) 240 cm2

c) 256 cm2

d) 400cm2


(with solution pls)

Expert's answer

24. The volume of prismatoid is given by this formula:


V=L6(A1+4Am+A2)V=\dfrac{L}{6}(A_1+4A_m+A_2)

where

A1A_1 and A2=A_2= areas of parallel bases

Am=A_m= area of the section midway between A1A_1 and A2A_2

L=L= the altitude


V=1006(90+4(120)+210)=13000(cm3)V=\dfrac{100}{6}(90+4(120)+210)=13000(cm^3)

c) 13 000 cm3



25. a=12 cm,b=20 cm,h=14 cma=12\ cm, b=20\ cm, h=14\ cm


cotα=xa/2=x+h/2m/2=x+hb/2\cot\alpha=\dfrac{x}{a/2}=\dfrac{x+h/2}{m/2}=\dfrac{x+h}{b/2}

bx=ax+ahbx=ax+ah

x=ahba=12(14)2012=21(cm)x=\dfrac{ah}{b-a}=\dfrac{12(14)}{20-12}=21(cm)

m=a(x+h/2)x=12(21+14/2)21(cm)=16(cm)m=\dfrac{a(x+h/2)}{x}=\dfrac{12(21+14/2)}{21}(cm)=16(cm)

Am=m2=(16)2=256(cm2)A_m=m^2=(16)^2=256(cm^2)

c) 256 cm2



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