Consider frustrum of a regular hexagonal pyramid
Let a1= the upper base edge, a2= the lower base edge, and L= the slant height.
The lateral area AL of the frustum of a regular pyramid is
AL=21n(a1+a2)L The lateral area AL of the frustum of a regular hexagonal (n=6) pyramid is
AL=21(6)(a1+a2)L
160=21(6)(5+8.5)L
L=40.5160m≈3.95m
b) 3.95 m
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