h=36.64cm,a=40cmh=36.64cm, a = 40cmh=36.64cm,a=40cm
find the base angles of one of the triangle as follows,
360o5=72o\frac{360^{o}}{5} =72^{o}5360o=72o
each base angle = 180o−72o2=54o\frac{180^{o} - 72^{o}}{2}=54^{o}2180o−72o=54o
volume of the pentagonal pyramid is given by,
V=512tan(54o)ha2=512tan(54o)×36.64×402=33,620.42cm3V=\frac{5}{12}tan(54^{o})ha^{2}= \frac{5}{12}tan(54^{o})\times36.64\times40^{2}= 33,620.42cm^{3}V=125tan(54o)ha2=125tan(54o)×36.64×402=33,620.42cm3
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