An 11 m ladder is placed 4 m away from the wall. If Joey, who is 1.7 m tall, stood up on top of the ladder,
how high would the top of his head be in relation to the floor?
Ladder=11mFloor=4mfloor to Joey’s feet =yAccording to pythagoras theorem,42+y2=112y2=112−42y2=121−16y2=105y=10.25m\textsf{Ladder}= 11m\\ \textsf{Floor} = 4m\\ \textsf{floor to Joey's feet } = y\\ \textsf{According to pythagoras theorem,}\\ 4^2 + y^2 = 11^2\\ y^2 = 11^2 - 4^2\\ y^2 = 121 - 16\\ y^2 = 105\\ y = 10.25mLadder=11mFloor=4mfloor to Joey’s feet =yAccording to pythagoras theorem,42+y2=112y2=112−42y2=121−16y2=105y=10.25m
From the diagram above,
x=y+1.7mx=10.25m+1.7mx=11.95mx = y + 1.7m\\ x = 10.25m + 1.7m\\ x = 11.95m\\x=y+1.7mx=10.25m+1.7mx=11.95m
∴11.95m\therefore 11.95m∴11.95m is how high the top of his head would be in relation to the floor.
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