Question

J is between H and K. If HJ = 6x - 5, JK = 4x -6, and KH = 129, find the value of x.

Answer 1

HK = KH = 129

HJ = 6x - 5

JK = 4x - 6

HK = HJ + JK

HK = 6x - 5 + 4x - 6

HK = 6x + 4x - 5 - 6

HK = 10x - 11

Since HK = 129

Therefore,

10x - 11 = 129

10x = 129 + 11

10x = 140

Divide both sides by 10

$\frac{10x}{10} = \frac{140}{10}$

x = 14