Let "\\angle DBQ=x\\degree", so "\\angle PBD=60\\degree-x\\degree".
"\\angle ABP=60\\degree-\\angle PBD=60\\degree-(60\\degree-x\\degree)=x\\degree."
If "\\angle ABP=\\angle DBQ", "\\angle BAP=\\angle BDQ", "AB=BD", so "\\triangle ABP=\\triangle DQB"
and "BP=BQ".
In "\\triangle PBQ: \\angle PBQ=60\\degree, PB=BQ", so "\\angle QPB=\\angle PQB=\\frac{180\\degree-\\angle PBQ}{2}=60\\degree".
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