Answer to Question #138976 in Geometry for Nick

Question

What is the weight of a steel plate 15 ft. long, 4 ft. wide, and 5/8 in,
thick, if the steel weighs 475 lbs/f

Answer 1

Explanations & Calculations

• $\small m=v \rho$ is the equation usually employed in these kinds of questions.
• Therefore,

$\qquad\qquad \begin{aligned} \small V&= \small 15ft\times4ft \times\frac{5}{8}\times\Big(\frac{1}{12}ft\Big)\\ &= \small \frac{25}{8}ft^3 \end{aligned}$

• Therefore the weight of the plate is,

$\qquad\qquad \begin{aligned} \small m&= \small \frac{25}{8}ft^3\times475 lbsft^{-3}\\ &=\small \bold{1484.375lbs} \end{aligned}$