Let suppose n number of tiles is required to covered the whole canvas,
Area of 1 tile="(side)^2"
="6^2"
=36 square units
so Area of canvas ="n\\times" Area of 1 tile
=36n square units
Case:- If the canvas is of square shape the side of canvas
="\\sqrt{area of canvas}"
="\\sqrt{36n}"
=6"\\sqrt{n}" units
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