Point D is on line segment \overline{CE}
CE
. Given CE=18
CE=18 and CD=12,
CD=12, determine the length \overline{DE}.
DE
.
Here is the Sketch
CD‾+DE‾=CE‾\overline{CD} + \overline{DE} = \overline{CE}CD+DE=CE (segment addition postulate)
But,
CD=12CD = 12CD=12 And
CE=18CE =18CE=18
∴12+DE=18\therefore 12 +DE = 18∴12+DE=18 (plugging in known values)
DE=18−12DE = 18 - 12DE=18−12
DE‾=6\overline{DE} = 6DE=6 (final answer)
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