We draw a horizonal line PR and point Q somewhere on the line.
PQ=5x−4PQ=5x-4PQ=5x−4
QR=xQR=xQR=x
PR=2xPR=2xPR=2x
PQ+QR=PRPQ+QR=PRPQ+QR=PR
5x−4+x=2x5x-4+x=2x5x−4+x=2x
Solve for x
5x+x−2x=45x+x-2x=45x+x−2x=4
4x=44x=44x=4
x=1x=1x=1
Now we substitute the value of x in PR.
PR=2⋅1=2PR=2 \cdot 1=2PR=2⋅1=2
Answer: 2.
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