m<SXT=m<QXS+m<QXT⇒125+2x−2=4x+1125−2−1=4x−2x2x=122x=61°∴m<QXS=2x−2=2(61)−2=122−2=120°m<\textrm{SXT} = m<\textrm{QXS} + m<\textrm{QXT}\\ \Rightarrow 125 + 2x - 2 = 4x + 1 \\ 125 - 2 - 1 = 4x - 2x \\ 2x = 122\\ x = 61\degree\\ \therefore m<\textrm{QXS} = 2x - 2 = 2(61) - 2 = 122 - 2 = 120\degreem<SXT=m<QXS+m<QXT⇒125+2x−2=4x+1125−2−1=4x−2x2x=122x=61°∴m<QXS=2x−2=2(61)−2=122−2=120°
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