Answer to Question #134410 in Geometry for Sara

Question

M<SXT=(4x+1), m<QXS=(2x-2), and m<QXT=125. Find the value of x and m<QXS

Answer 1

$m<\textrm{SXT} = m<\textrm{QXS} + m<\textrm{QXT}\\ \Rightarrow 125 + 2x - 2 = 4x + 1 \\ 125 - 2 - 1 = 4x - 2x \\ 2x = 122\\ x = 61\degree\\ \therefore m<\textrm{QXS} = 2x - 2 = 2(61) - 2 = 122 - 2 = 120\degree$