PQ+QR=PRPQ+QR=PRPQ+QR=PR
If PQ=2xPQ=2xPQ=2x, QR=5xQR=5xQR=5x and PR=7PR=7PR=7, then
2x+5x=72x+5x=72x+5x=7
7x=77x=77x=7
x=1x=1x=1
Calculate the value of QRQRQR:
QR=5x=5∗1=5QR=5x=5*1=5QR=5x=5∗1=5
Solution: QR=5QR=5QR=5.
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