Answer to Question #119455 in Geometry for Christine

Question

A cow is tethered to a ring on outside wall of a barn 10 meters from the corners. The barn is 20 meters wide and 40 meters long. The rope is 50 meters in length. Find the cows grazing area. There is 2 answers to problem. Need to find both.

Answer 1

First way:

A = $(\pi*50^2)/2$

B=C=$(\pi*40^2)/4$

X=A+B*2= $(3.14*50^2)/2 + ((3.14*40^2)/4)*2$

X=$3925+2512=6437m^2$

Second way:

A=$(\pi*50^2)/2$

B=$(\pi*40^2)/4$

C=D=$(\pi*20^2)/4$

X=A+B+C*2=$(3.14*50^2)/2+(3.14*40^2)/4+((\pi*20^2)/4)*2$

X=3925+1256+628=5809$m^2$