Question #119455
A cow is tethered to a ring on outside wall of a barn 10 meters from the corners. The barn is 20 meters wide and 40 meters long. The rope is 50 meters in length. Find the cows grazing area. There is 2 answers to problem. Need to find both.
1
Expert's answer
2020-06-01T19:27:44-0400

First way:


A = (π502)/2(\pi*50^2)/2

B=C=(π402)/4(\pi*40^2)/4

X=A+B*2= (3.14502)/2+((3.14402)/4)2(3.14*50^2)/2 + ((3.14*40^2)/4)*2

X=3925+2512=6437m23925+2512=6437m^2


Second way:



A=(π502)/2(\pi*50^2)/2

B=(π402)/4(\pi*40^2)/4

C=D=(π202)/4(\pi*20^2)/4

X=A+B+C*2=(3.14502)/2+(3.14402)/4+((π202)/4)2(3.14*50^2)/2+(3.14*40^2)/4+((\pi*20^2)/4)*2

X=3925+1256+628=5809m2m^2



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