Let VA be the volume of cylinder, VB be the volume of cone. We know that VA=πrA2hA, VB=πrB2hB/3 , where h is the height and r is the radius. hA=hB and rA=rB by conditions of the problem. We have
VB=πrb2hb/3=πrA2hA/3=VA/3==18π/3=6π=18.84cm3≈19cm3.
Answer: 19cm3.
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