Let "V_A" be the volume of cylinder, "V_B" be the volume of cone. We know that "V_A = \\pi r_A^2h_A", "V_B = \\pi r_B^2h_B\/3" , where "h" is the height and "r" is the radius. "h_A = h_B" and "r_A = r_B" by conditions of the problem. We have
"V_B = \\pi r_b^2h_b\/3 = \\pi r_A^2h_A\/3 = V_A\/3= \\\\=18\\pi\/3=6\\pi= 18.84cm^3 \\approx 19 cm^3."
Answer: "19cm^3".
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