Question #105046

A lateral edge of the hexagonal pyramid is 2.0m long and its base perimeter is 6m determine the volume of the pyramid and its lateral area

Expert's answer

Volume of Hexagonal pyramid is given by 32a2h\dfrac{\sqrt3}{2}a^2h ; where a is the base edge and h is the height

base perimeter = 6*a

6=6*a

a=1 m

lateral edge =a2+h2\sqrt{a^2+h^2} =12+h2=2,=\sqrt{1^2+h^2}=2,

h=3h=\sqrt{3}

Volume = 32a2h\dfrac{\sqrt3}{2}a^2h =32123=3/2\dfrac{\sqrt3}{2}1^2\sqrt3=3/2


Lateral surface area = 3ah2+3a24=3∗1∗3+3/4=315/23a\sqrt{h^2+\dfrac{3a^2}{4}}=3*1*\sqrt{3+3/4}=3\sqrt{15}/2



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