Question

Find Tge measure of <Q if m<R=7x-26 and m<P=5x-2

Answer 1

Given

$$\angle R =7x-26 \space and \space \angle P=5x - 2$$

We know sum of the angles in a triangle is equal to $180^o$

So,

$$\angle P + \angle Q + \angle R = 180$$

$$5x-2+ 7x-26+ \angle Q=180$$

Now solve for $\angle Q$

$$\angle Q=180-12x +28$$

$$\angle Q=208-12x$$

Answer:

$$Measure \space of \space Angle \space Q= \angle Q=(208-12x)^{\circ}$$