Question #100411
Draw triangle xyz with vertices x(-3,2),Y(4,-2), and z(-3,-2) on the coordinate plane.Then find the area of the triangle in square units
1
Expert's answer
2019-12-18T12:03:17-0500

Area=12x1(y2y1)+x2(y3y1)+x3(y1y2)Area=\frac{1}{2}|x_1(y_2-y_1)+x_2(y_3-y_1)+x_3(y_1-y_2)|

Plugging values,

x1=3,x2=4,x3=3x_1=-3,x_2=4,x_3=-3

y1=2,y2=2,y3=2y_1=2,y_2=-2,y_3=-2

Plugging the values in above formula,

Area=12(3)[2(2)]+4(22)+(3)[2(2)]Area=\frac{1}{2}|(-3)[-2-(-2)]+4(-2-2)+(-3)[2-(-2)]|

Area=12(3)[2+2]+4(22)+(3)[2+2]Area=\frac{1}{2}|(-3)[-2+2]+4(-2-2)+(-3)[2+2]|

Area=12(3)[0]+4(4)+(3)[4]Area=\frac{1}{2}|(-3)[0]+4(-4)+(-3)[4]|

Area=1201612Area=\frac{1}{2}|0-16-12|

Area=1228Area=\frac{1}{2}|-28|

Area=12×28Area=\frac{1}{2} \times{28}

Area=14Area=14

So, area = 14 square units.


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