Question #70186

show that a norm on a vector space X is a sublinear functional on X
1

Expert's answer

2017-09-25T13:29:06-0400

Answer on Question #70186 – Math – Functional Analysis

Question

Show that a norm on a vector space XX is a sublinear functional on XX.

Solution

Let's f(x)=xf(x) = ||x||. Obviously, f(x)f(x) is a function from a vector space XX to the scalar field R\mathbb{R}.

1. xX,aR+,f(x)=ax=ax=ax=af(x),due to the multiplicative property of a norm.\forall x\in X,\quad \forall a\in \mathbb{R}_{+},\quad f(x) = ||a\cdot x|| = |a|\cdot ||x|| = a\cdot ||x|| = a\cdot f(x),\quad \text{due to the multiplicative property of a norm.}

2. x,yX,f(x+y)=x+yx+y=f(x)+f(y),\forall x, y \in X, f(x + y) = ||x + y|| \leq ||x|| + ||y|| = f(x) + f(y), because of the triangle inequality.

Correctness of the statement and both properties (positive homogeneity and subadditivity) were proved.

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