Question #41274

range of function cos(sinx)

Expert's answer

Answer on Question # 41274– Math - Functional Analysis

Question:

Find range of function cos(sinx)\cos(\sin x)

Solution:

Range of y(x)=sin(x)y(x) = \sin(x) is {yR:1y1}\{y \in R : -1 \leq y \leq 1\}. So, to find range of z(x)=cos(sinx)z(x) = \cos(\sin x), we should find a range of z(y)=cos(y)z(y) = \cos(y) with domain {yR:1y1}\{y \in R : -1 \leq y \leq 1\}. And it is easily seen that the range of this function is {zR:cos(1)z1}\{z \in R : \cos(1) \leq z \leq 1\}

Answer: {zR:cos(1)z1}\{z \in \mathbb{R} : \cos(1) \leq z \leq 1\}

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