The formula for compound interest
A=P(1+nr)ntA= the future value of the investment/loan, including interest
P = the principal investment amount
r = the annual interest rate (decimal)
n = the number of times that interest is compounded per unit t
t = the time the money is invested or borrowed for
We have that P0=2000,r=0.07,n=4
At the end of the second year
A2=P0(1+(1+nr)n) At the end of the third year
A3=P0(1+(1+nr)n+((1+nr)n)2) We see the geometric series
Sk=1⋅1−(1+nr)n1−((1+nr)n)k Then
Am=P0Sm=P0⋅1−(1+nr)n1−((1+nr)n)m How much will he have in the account at the end of 5 years?
A6=2000⋅1−(1+40.07)41−((1+40.07)4)6=14373.78 He will have in the account at the end of 5 years RM 14373.78.
Comments