Let number of years = n = 5, annual interest = r = 7% = 0.07, number of compounds = m = 4, deposit = R = 2000.
Value Ak of deposit R after k years Ak = R*(1+r/m)k*m.
Future value of the first deposit An = R*(1+r/m)n*m
Future value of the second deposit An-1 = R*(1+r/m)(n-1)*m
.......
Future value of the last deposit A0= R*(1+r/m)0*m
S = A0 + A1 + .. + An = R*(1+r/m)0*m+ R*(1+r/m)1*m+... + R*(1+r/m)n*m =
(this is sum of geometric series with ratio = (1+r/m)m )
=R*( (1+r/m)(n+1)*m-1 )/( (1+r/m)m-1 )
S = 2000( (1+0.07/4)6*4-1 )/( (1+0.07/4)4-1 ) = 14373.7753523
Answer: 14373.7753523
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