If 35 000 accumulates to 48 328 at a continuous compounded rate of year then the term under consideration is
Solution
Using the Formula
"A=Pe^{rt}"
Here "A" is the amount accumulated, "P" is the principal amount invested, "r" is the interest rate and "t" is the tenure.
Therefore, we can write,
"48328=35000(e^{rt})"
"e^{rt}=\\frac{48328}{35000}"
"e^{rt}=1.3808"
"ln(e^{rt})=ln(1.3808)"
"rt\\times ln(e)=ln(1.3808)"
"rt\\times (1)=ln(1.3808)"
"t=\\frac{ln(1.3808)}{r}"
Therefore, knowing the value of "r", we can find the tenure.
For example if "r=6.8\\%"
Then
"t=\\frac{ln(1.3808)}{6.8\\%}"
"t=\\frac{ln(1.3808)}{0.068}"
"t=4.745" years
Comments
Leave a comment