Consider a woman puts Php 60000 in an account. After 3 years, she has a total amount of Php 70000. How long will it take to have Php 100000?
Pi=P(1+r100)nP_i=P(1+ \frac{r}{100})^nPi=P(1+100r)n
70000=60000(1+r100)370000=60000(1+ \frac{r}{100})^370000=60000(1+100r)3
r=100(70000/600003−1)=5,27r=100(\sqrt[3]{70000/60000}-1)=5,27r=100(370000/60000−1)=5,27
100000=60000(1+5,27100)n100000=60000(1+\frac{5,27}{100})^n100000=60000(1+1005,27)n
n=log1.0527(100000/60000)=9.946n=log_{1.0527}(100000/60000)=9.946n=log1.0527(100000/60000)=9.946
Answer: It takes 9.946 year
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments