Question #268171

2 months ago Michael deposited R9000 into savings account at a simple interest rate of 11.5% per year. He also deposited R5000 six months ago into another savings account earning 8% per year compounded half yearly. The total amount of Michael's savings in 3 years time is

1
Expert's answer
2021-11-24T18:19:14-0500

Simple interest


A=P(1+rt)A=P(1+rt)


Time (t)t) is 3years+212months3 years +\frac{2}{12} months


A=9000(1+(0.1153.167))A = 9000(1+(0.115*3.167))


A=A = R12,277.85R12,277.85


Compound interest


A=P(1+rn)ntA = P(1+\frac{r}{n})^{nt}


Time (tt) is 3years+612months3 years + \frac{6}{12} months


A=5000(1+0.082)23.5A = 5000(1+\frac{0.08}{2})^{2*3.5}


A=R6,579.66A = R 6,579.66


Total amount


TA=TA = R12,277.85R12,277.85 ++ R6,579.66R6,579.66


TA=R18,857.51TA = R18,857.51


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