Jane plans to retire in 30 years and would like to have $500,000 in her account. If the interest on her account is 3.92% compounded monthly, how much should she put into her account every month?
a. $1,633.33 b. $1,388.89 c. $730.74 d. $653.33
"A=\\frac{P[(1+\\frac{r}{n})^{nt}-1]}{\\frac{r}{n}}"
A"=" $ 500,000
r"=" "\\frac{3.92}{1200}" Compounded monthly
n"=" 12
t"=" 30 years
P"=?"
"\\$500,000=\\frac{P[(1+\\frac{3.92}{1200})^{12\u00d730}-1]}{\\frac{3.92}{1200}}"
"\\$500,000=684.24P"
"P=\\$730.74"
"\\therefore" Jane should put "\\$" 730.74 into her account every month
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